The molar conductivity of acetic acid at infinite dilution is 387 ohm-1 cm2 / mol. At the same temperature, but at a concentration of 1 mole in 1000 litres, it is 55 ohm-1 cm2 / mol. what is the percentage dissociation of acetic acid?
Answers
Answer:
The percentage of dissociation of acetic acid is 14.2%
Explanation:
Given data:
molar conductivity of acetic acid at infinite dilution = 387 ohm^-1 cm^2 / mol.
=molar conductance of solution at particular or specific concentration
The temperature is maintained constant.
concentration of 1 mole in 1000 litres = 55 ohm^-1 cm^2 / mol
= Molar conduction at infinite dilution
To find:
the percentage dissociation of acetic acid
Solution:
We know that
Aplha = a = degree of dissociation
= molar conductance of solution at particular or specific concentration/
Molar conduction at infinite dilution
=55/387
= 0.142
Percentage of degree of dissociation= 0.142*100
=14.2%
Hence,
The percentage of dissociation of acetic acid is 14.2%
Note= The degree of dissociation cannot be greater than 1.
Explanation:
Given that,
Molar conductivity (^m)= 55 ohm-1 cm2
Infinite dilution^° = 387 ohm-1 cm2
we know that,
1mol in 1000 litres
=0.001 mol-2 = 0.001M
So,
For 0.001 M (CH3COOH), a = ^m/^°
That's , a = 55/387
a = 0.1421 = 14.21%