the molar fraction of h2 when solution contain equall masses of h2 and he
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I hope it's helpfull
Explanation :
Equal mass of H 2
, He and CH 4are mixed in an empty container at 300 K when total pressure is 2.6 atm. The partial pressure of H 2
1.6 atm
We know that partial pressure of a gas is the product of the total pressure and the concentration or the mole fraction of a gas in the mixture.
Partial pressure = Total pressure × Mole fraction
Let the given mass of each gas be x.
We know that the atomic masses given below:
H 2 =2He=4CH 4=16
So, we have the mole fraction of each gas which is given below:
H 2=x/2
He=x/4
CH 4 =x/16
The total moles of the gas mixture =0.8125x
Now, to calculate the partial pressure of :H
2Partial pressure = Total pressure × Mole fraction
= 0.8125x2x
×2.6Partial pressure of H 2=1.6 atm
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