Question

The molar heat capacity at constant pressure of an
ideal gas mixture is 8R/3. The ratio of molar heat
capacities at constant pressure to constant volume
for this mixture will be
(1) 1.5
(2) 1.4
(3) 1.6
(4) 1.2​

Answer 1

Answer:

See the attachment

Good luck

Explanation:

Answer 2

Answer:

The correct option is 3.

Explanation:

$C_p-C_v=R\\\frac{8R}{3} -C_v=R\\C_v=\frac{5R}{3} \\Also,\\\frac{C_p}{C_v} =r$

$\frac{\frac{8R}{3} }{\frac{3}{5R} }$=r

Hence r=1.6

Molar heat capacity is defined as the amount of heat required to raise 1 mole of a substance by 1 degree Kelvin.[2] Molar heat capacity is very similar to specific heat capacity, but it is measured per mole instead of per gram of a substance. Molar heat capacity is an intensive property (it does not change with the amount of substance). The SI unit of molar heat capacity is Joule per mole per Kelvin, [3].

To find the number of moles () of a substance, divide the mass of the sample (in grams) by its molar mass (in grams/mol): .

The equation for molar heat capacity does not apply if there is a phase change because the heat added or removed during the phase change does not change the temperature.[4]

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