The molar heat capacity of water at constant pressure, CP is 75JK−1mol−1. When 1.0 kJ of heat is supplied to 100 g of water which is free to expand, the increase in temperature of water is
Answers
Answered by
143
use the formula: (∆Q)heat energy = moles×Cp×∆T
10^3(kJ) = 100/18 (moles) × 75 × ∆T
by simplifying we get
∆T = 2.4 kelvin
10^3(kJ) = 100/18 (moles) × 75 × ∆T
by simplifying we get
∆T = 2.4 kelvin
Answered by
31
use the formula: (∆Q)heat energy = moles×Cp×∆T
10^3(kJ) = 100/18 (moles) × 75 × ∆T
by simplifying we get
∆T = 2.4 k
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