The molar mass of carbon dioxide (CO2) is 44.01 g/mol. The molar mass of water (H2O) is 18.01 g/mol. A reaction uses 528 g of CO2. How many moles of water are used in this reaction?
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The molar mass of carbon dioxide {CO₂} = 44.01 g/mol ≈ 44 g/mol
molar mass of water ( H₂O ) = 18.01 g/mol ≈ 18 g/mol
reaction is,
H₂O + CO₂ -------> H₂CO₃
hence, 1 mole of Carbon dioxide react with 1 mole of water and make 1 mole of H₂CO₃ .
Given, mass of carbon dioxide = 528 g
mole of Carbon dioxide = 528/44 = 12 mole
∵ 1 mole of Carbon dioxide reacts with 1 mole of water
∴ 12 mole of Carbon dioxide react with 12 mole of water .
Hence, the number of mole of water = 12
molar mass of water ( H₂O ) = 18.01 g/mol ≈ 18 g/mol
reaction is,
H₂O + CO₂ -------> H₂CO₃
hence, 1 mole of Carbon dioxide react with 1 mole of water and make 1 mole of H₂CO₃ .
Given, mass of carbon dioxide = 528 g
mole of Carbon dioxide = 528/44 = 12 mole
∵ 1 mole of Carbon dioxide reacts with 1 mole of water
∴ 12 mole of Carbon dioxide react with 12 mole of water .
Hence, the number of mole of water = 12
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