The molar mass of copper(II) chloride (CuCl2) is 134.45 g/mol. How many formula units of CuCl2 are present in 17.6 g of CuCl2
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MM of CuCl₂ = 134.45 g/mol
Weight of CuCl₂ = 17.6 g
Number of moles of CuCl₂ is 17.6/134.45
Number of formula units of CuCl₂ in one mole equals avogadro number, i.e. 6.022×10²³. Number of formula units of CuCl₂ in this case = 17.6/134.45×6.022×10²³ = 7.883×10²²
Weight of CuCl₂ = 17.6 g
Number of moles of CuCl₂ is 17.6/134.45
Number of formula units of CuCl₂ in one mole equals avogadro number, i.e. 6.022×10²³. Number of formula units of CuCl₂ in this case = 17.6/134.45×6.022×10²³ = 7.883×10²²
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Given ⇒
Molar mass of the copper chloride = 134.5 g/mole.
Mass of the Copper chloride = 17.6 g.
Now, Using the Formula,
No. of Moles = Mass/Molar mass.
∴ No. of moles of the Copper chloride = 17.6/134.5
= 0.13 moles.
We know, number of the formula units is equal to the number of the molecules,
∴ No. of Formula units = No. of moles × Avogadro's number.
= 0.13 × 6.022 × 10²³
= 0.783 × 10²³
= 7.83 × 10²².
Thus, the formula units of the copper chloride is 7.83 × 10²².
Hope it helps.
Molar mass of the copper chloride = 134.5 g/mole.
Mass of the Copper chloride = 17.6 g.
Now, Using the Formula,
No. of Moles = Mass/Molar mass.
∴ No. of moles of the Copper chloride = 17.6/134.5
= 0.13 moles.
We know, number of the formula units is equal to the number of the molecules,
∴ No. of Formula units = No. of moles × Avogadro's number.
= 0.13 × 6.022 × 10²³
= 0.783 × 10²³
= 7.83 × 10²².
Thus, the formula units of the copper chloride is 7.83 × 10²².
Hope it helps.
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