The molar ratio of O2 and CH4 in a mixture of 1: 1 mass ratio of O2 and CH4 is :
Answers
Answer:
The rate of effusion of a gas with molar mass M at pressure P, and the hole area A at a temperature T is :
r=
2πMRT
PA
Thus for a mixture of gases with mass ratio m
1
:m
2
r
2
r
1
=
P
2
P
1
×
M
1
M
2
P∝n (number of moles)
n=mass/Molar mass
Thus for a mixture of O
2
and CH
4
in 3:2 mass ratio :
P
CH
4
P
O
2
=
M
O
2
m
O
2
×
m
CH
4
M
CH
4
Given
m
CH
4
m
O
2
=
2
3
and M
CH
4
=16 and M
O
2
=32
upon substitution we get :
P
CH
4
P
O
2
=
32
3
×
2
16
=
4
3
r
CH
4
r
O
2
=
P
CH
4
P
O
2
M
O
2
M
CH
4
=
4
3
32
16
=
4
2
3
The relative rates of effusion of O2 to CH4 through a container containing O
2
and CH
4
in 3:2 mass ratio will be
4
2
3
The correct option is B.
Explanation:
hope its help u
Answer:
3/4√2
Explanation:
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