Question

The molar solubility of CaF, (K = 5.3 * 10-11) in
0.1 M solution of NaF will be
[NEET-2019 (Odisha)]
(1) 5.3 * 10-10 mol L-1 (2) 5.3 * 10-11 mol L-1
(3) 5.3 * 10-8 mol L-1 (4) 5.3 * 10-9 mol L-1​

Answer 1

Answer:

option c is the answere of this question