Question

The molar specific heat of a gas at constant volume is 12307.69 J kg K-1. If the ratio of the
two specific heats is 1.65, calculate the difference between the two molar specific heats of
gas.
(a) 7999 J kg K-1
(c) 6890 J kg K-1
(b) 7245 J kg- K-1
(d) 4067 J kg K-1​

Answer 1

so, the answer is ((a) 7999 J Kg K-1

we have to find the difference between the two molar specific heats of gas

Explanation:

Given

Ratio of two specific heats

C p / C v=1.65     …. (1)

molar specific heat of a gas at constant volume is  C v= 12307.69 J kg k-1

so by equation (1)

C p/12307.69=1.65

C p=20307.68 J kg K-1

so the difference between the two molar specific heats of gas is

C p-C v=20307.68-12307.69=7999 j kg K-1