Chemistry, asked by shabaz1031, 1 year ago

The molarity of 0.04N Ba[OH]2 as a base is?

Answers

Answered by tusharanandgr563

7

Answer:

Explanation:Normality =Molarity *n factor

So Molarity =Normality/n factor

N factor of barium =2

Molarity = 0.04/2

= 0.02M

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