The molarity of 10 ml of 22.4 V H2 O2 is
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Answer:
X11.2
Explanation:
Concentration of commercially available H2O2 solutions (as in pharmacy etc) is expressed as “X volume H2O2” solution(where X is a number). It means, 1 volume of such solution will give X volume of O2 at STP when completely decomposed (H2O2 is unstable and would eventually decompose to give H2O and O2).
Now, Let us assume, 1 litre of such solution produces X litres of O2 at STP.
Hence, moles of O2 = X/22.4
So, the original moles of H2O2 that were present in that solution as per the equation
H2O2→H2O+12O2
Moles of H2O2 =2X22.4=X11.2
And, the volume of that solution taken was = 1 liter
Therefore, Molarity =X11.2
Now, your question.
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