Question

The Molarity of 200ml of HCl solution which can neutralize 10.6g of anhydrous Na2Co3
A) 0.1M B)0.5M. C)0.75M D)1M​

Answer 1

Answer:

D)1M

Explanation:

1 mole of Na2co3 will react with 2moles of Hcl.

ie,Na2co3 +2Hcl.....2Nacl +co2 +H2O 106gm.of Na2co3 will react with 2*36.5=73 gm of Hcl.

so,10.6gm of Na2co3 will be neutralized by 7.3gm of Hcl.

1000 ml.of 1M Hcl solution contains=36.5gm.

200ml.of 1 M Hcl solution contains=36.5/5=7.3

so the molarity of Hcl required of neutralize 10.6gm sodium carbonate is

200ml.of 1M HCl.#####