Question

The molarity of 24.5%(w/w) h2so4 solution having density 1.2g/ml

Answer 1

solution : use the formula,

molarity = x × d × 10/M

where , x = percentage by weight of solute.

d = density of solution.

and M = molecular mass of solute.

here solute is sulphuric acid so, molecular mass of solute, M = molecular mass of sulphuric acid = 98 g/mol

here, x = 24.5 , d = 1.2g/ml and M = 98

so, molarity = (24.5 × 1.2 × 10)/98

= 3

hence, molarity of the solution is 3molar.