Question

the molarity of 5%(w/v) sucrose solution if the density of solution is 2.5g/ml in mol/L is? ​

Answer 1

Answer:

0.15

Explanation:

5%(w/v)=5g of sucrose in 100ml of the solution

thus, given weight of sucrose=5g

        molecular weight of sucrose (C12H22O11)= (12x12)+(1x22)+(16x11)

                                                                              =324g

now, no. of moles of sucrose =given weight/molecular weight

                                                 =5/324 =0.015

also volume of the solution =100ml=0.1L

thus, molarity =no.of moles of sucrose/volume os the solution

                       =0.015/0.1 =0.15mol/L

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Answer 2

Answer:

0.15M

Explanation:

5/342 /0.1

0.15