Question

The molarity of 500 mL aqueous solution containing
36.5 g of HCl​

Answer 1

Answer:

2M

Explanation:

moles of HCl= weight/molecular weight

=36.5/(1+35.5)

=1 mol

now,

molarity = moles of solute/volume of solution

also, 1L = 1000ml

so, 500mL = 0.5 L = volume of solution

hence,

Molarity= 1/0.5= 2M