Question

the molarity of a glucose solution containing 36 g of glucose per 400 ml of the solution is

Answer 1

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Answer 2

The molarity of glucose solution is 0.5 M

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of solute (glucose) = 36 grams

Molar mass of solute (glucose) = 180 g/mol

Volume of solution = 400 mL

Putting values in above equation, we get:

$\text{Molarity of glucose solution}=\frac{36\times 1000}{180\times 400}\\\\\text{Molarity of glucose solution}=0.5M$

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