The molarity of a sodium chloride 2 po
solution by dissolving 4 gram of it,
in 250 ml of water is
Answers
Answered by
3
Answer:
GMW = Gram Molecular Weight of the solute = 40g. V = Volume of the solution in ml. = 250 ml. So, M of NaOH = 4 × 1000 / 40 × 250 = 0.4 M.
Answered by
0
Answer:
2.72g/lit.
Explanation:
Molarity = no. of moles of solute/ volume of solution (in lit.)
=(wt./ M.Wt.)×(1000/250)
= 0.68×4
= 2.72g/lit.
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