Chemistry, asked by sonals676, 8 months ago

The molarity of a sodium hydroxide solution by dissolving 4 grams of it in 250 ml aqueous solution.
(a) 0.8 M
( b) 0.1 M
(c) 0.2 M
(d) 0.4 M

Answers

Answered by Draxillus
3

\green{Given}

  • Mass of NaOH = 4 gram.

  • Volume of the solution = 250 ml

 \green{To  \: Find }

Molarity of the solution

 \green{Formula}

 \boxed{ \blue{molarity \:  =  \frac{no \: of \: moles \: of \: solute}{volume \: of \: solution}  \: } \: }

 \green{Calculations}

We know, Molar mass of NaOH = 40 gram.

Hence, number of moles of NaOH in its 4 gram solution =

 \pink{ \frac{given \: mass}{molar \: mass} \: \:  =  \frac{4}{40}   = 0.1}

Using formula of molarity ( Volume = 250 ml = 0.250 l )

 \boxed{molarity \:  =  \frac{0.1}{0.250}  = 0.4 \: }

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