Question

The molarity of a solution of H2SO4 is 1.35 M. calculate its molality.(Density of solution=1.02g/cm^3)​

Answer 1

Answer:1.52 moles /litre

Explanation: its in the photo

Answer 2

Molality of the solution is 1.32 mol/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

$Molarity=\frac{n}{W_s}$

where,

n = moles of solute

$W_s$ = weight of solvent in kg

Given :moles of $H_2SO_4$ (solute) = 1.35 moles in 1000 ml of solution    

mass of water (solvent )= $density\times {\text {volume}}=1.02g/ml\times 1000ml=1020g$

Now put all the given values in the formula of molality, we get

$Molality=\frac{1.35\times 1000}{1020g}=1.32mole/kg$

Therefore, the molality of solution is 1.32 mole/kg

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