the molarity of solution containing 2.8% mass by volume solution of KOH is
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Answered by
147
2.8% by mass means 2.8 g in 1l soln.
molarity=moles/volume(liter).
molar mass of KOH=39+16+1=56
moles=2.8/56=0.05
molarity=0.05/1=0.05
molarity=moles/volume(liter).
molar mass of KOH=39+16+1=56
moles=2.8/56=0.05
molarity=0.05/1=0.05
Answered by
162
M(KOH) = 56g/ml
w = (mKOH/mSolution)x100% = 2.8%
c=?
c=n/V
n=m/M
assume that density of solution is approximately equal to density of water, therefore,ρ = 1g/ml
Suppose that, mSolution = 100g, therefore,
mKOH = w x mSolution/100% = 2.8x100/100% = 2.8g
mKOH = 2.8/56 = 0.05 mol
c = 0.05mol/0.1L = 0.5mol/L = M/5 (Answer).
w = (mKOH/mSolution)x100% = 2.8%
c=?
c=n/V
n=m/M
assume that density of solution is approximately equal to density of water, therefore,ρ = 1g/ml
Suppose that, mSolution = 100g, therefore,
mKOH = w x mSolution/100% = 2.8x100/100% = 2.8g
mKOH = 2.8/56 = 0.05 mol
c = 0.05mol/0.1L = 0.5mol/L = M/5 (Answer).
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