the molarity of solution obtained by mixing 750 ml of 0.5 m HCL with 250 ml of 2m HCL will be
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This question can be solved be the formula
molarity of mixing
M1V1+M2V2=M3V3
0.5*3/4+0.5*1/4=M3*1000
3/8+1/8/1000 = M3
0.25/1000=M3
0.00025
molarity of mixing
M1V1+M2V2=M3V3
0.5*3/4+0.5*1/4=M3*1000
3/8+1/8/1000 = M3
0.25/1000=M3
0.00025
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