Question

The molarity of solution of Cacl2 of on chemical analysis it is found that 200 ml of contain 3.01*10^22 ​

Answer 1

Explanation:

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moles \: of \: cl \\ \\ { \\ }^{2} 3.01 \times 10 |22| 6.02 \times 10 |23| \\ \\ 12 \times 10 | - 1 = 0.5 \times 10 | - 1 = 0.5 \times 10 | - 1 = 0.05 \\ \\ = 200ml = 0.2l = molarity = moles \: \frac{volume = 0.05 \frac{0.2 = m = 0.25mol \: l | - 1| }{?} }{?} | | | \times \frac{?}{?}

\begin{gathered}moles \: of \: cl \\ \\ { \\ }^{2} 3.01 \times 10 |22| 6.02 \times 10 |23| \\ \\ 12 \times 10 | - 1 = 0.5 \times 10 | - 1 = 0.5 \times 10 | - 1 = 0.05 \\ \\ = 200ml = 0.2l = molarity = moles \: \frac{volume = 0.05 \frac{0.2 = m = 0.25mol \: l | - 1| }{?} }{?} | | | \times \frac{?}{?}\end{gathered}

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