The molarity of solution of sodium chloride in water containing 5.85 gram of sodium chloride in 500 ml of solution is
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Answered by
46
As,. Molarity= no. of moles of solute/volume of solution in litres
Here solute is = NaCl (sodium chloride)
Now we have to find no. Of moles of NaCl
*_. Moles of NaCl=given mass/actual molar mass of NaCl
=5.85/58.5
=0.1 moles
As we are given vol of solution in Mili litre so we have to convert it into litre so,500ml=0.5 litre
Now to find molarity=no. of moles of solute/volume of solution in litres
=0.1/0.5
=0.2 moles
Here solute is = NaCl (sodium chloride)
Now we have to find no. Of moles of NaCl
*_. Moles of NaCl=given mass/actual molar mass of NaCl
=5.85/58.5
=0.1 moles
As we are given vol of solution in Mili litre so we have to convert it into litre so,500ml=0.5 litre
Now to find molarity=no. of moles of solute/volume of solution in litres
=0.1/0.5
=0.2 moles
Answered by
3
Explanation:
molarity = n/v
so n=m\ M
= 5.85/58.5 ( NaCl = 23+35.5= 58.5)
= 0.1 moles
molarity = 0.1/0.5 ( v= 500ml= 0.5 l)
= 0.2
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