Question

The molarity of the KOH solution which is 2.8% (mass/volume) solution is :

(A) M/10 (B) M/2 (C) M/5 (D) 1 M

Answer 1

2.8%m/v means 100ml of solution has 2.8g of KOH

Volume of solution=100ml=0.1L

Mass of KOH= 2.8g

Molar mass of KOH= 56

Moles(KOH) = Mass /Molar mass

Moles(KOH)=0.05

Molarity = moles(KOH)/Volume of

solution(L)

Molarity=0.05/0.1

Molarity=0.5M

I hope this helps ( ╹▽╹ )