Question

The molarity of the resultant solution obtained by mixing 1.5 L of 0.25 M aqueous HCL with 500 ml of 1 M aqueous HCL solution is

Answer 1

Answer:

1.5=0.25

1500=500

15=2.5

15=5

0.5 M

Answer 2

Given: A solution is obtained by mixing 1.5 L of 0.25 M aqueous HCl and 500 mL of 1 M aqueous HCl

To find: Molarity of the resultant mixture

Explanation: Molarity of first solution= 0.25 M

Volume of first solution= 1.5 L

Number of moles of first solution

= Molarity* Volume

= 0.25*1.5

= 0.375 moles

Molarity of second solution= 1 M

Volume of second solution= 500 mL

= 0.5 L

Number of moles of second solution

= Molarity* Volume

= 1 * 0.5

= 0.5 moles

Total number of moles= 0.375+0.5

= 0.875 moles

Total volume= 1.5+0.5 L

= 2 L

Resultant Molarity

= Total number of moles/ Total Volume

= 0.875 / 2

= 0.4375 M

Therefore, the the resultant molarity when 1.5 L of 0.25 M aqueous HCL is mixed with 500 ml of 1 M aqueous HCl, the resultant molarity is 0.4375 M.