Question

the molarity of the solution when 80 grams of NaOH is dissolved in 500 ml of solvent is​

Answer 1

Explanation:

The molecular weight of NaOH is 40 g/mol.

The number of moles of NaOH

40 g/mol

5 g

=0.125 moles.

500 ml water corresponds to0.500 L.

The molarity of the solution =

0.500 L

0.125 moles

=0.25

Answer 2

Answer: The molarity of solution is $1M$.

Explanation:

Molarity $(M)$ is defined as the number of moles of solute which are present in per liter of the solution.

$Molarity = \frac{no. of moles of solute }{Volume of solution}$

No. of moles of solute is the ratio of mass of the solute to the molecular mass of solute.

$no. of moles = \frac{w_{solute} }{M_{solute} }$

Here given mass of solute is $80 g$

Molecular mass of solute $(NaOH)$ is $40 g/mol$

$No. of moles of solute = \frac{80 g}{40 g / mol}= 0.5 moles$

Volume of solution is $500 mL (0.5 L)$

Molarity of the solution is:

$Molarity = \frac{0.5 moles }{ 0.5 L } = 1M$

Therefore the molarity of solution is $1M$.

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