Chemistry, asked by h00879uttam, 7 months ago

The mole fraction of a solvent in aqueous solution of a solute is 0.8.The molality (in mol kg⁻¹) of the aqueous solution is (A) 13.88 × 10⁻²
(B) 13.88 × 10⁻¹
(C) 13.88 (D) 13.88 × 10⁻³

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Answered by prashudwivedi54
5

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