Question

The mole fraction of CH3OH in an aqueous solution is 0.02 and its density is 0.994gcm-3,then the molality of the solution is

Answer 1

Answer:  Molarity of solution will be, 9.52 mole/L and the molality of solution will be, 13.38 mole/kg
Solution : Given,
Molar mass of = 32 g/mole
0.02 moles of in 0.08 moles of
Mass of (solute) =
Mass of =
Mass of solution = Mass of solute + Mass of solvent = 0.64+1.44 =2.08 g
Now we have to calculate the volume of solution.
 
Molarity : It is defined as the number of moles of solute present in one liter of solution.
Formula used :

where,
n = moles of solute = 0.02
= volume of solution in liter
= 0.0021 L
Now put all the given values in the formula of molarity, we get

Therefore, the molarity of solution will be, 9.52 mole/L
Molality : It is defined as the number of moles of solute present per kg of solvent.

n = moles of solute = 0.02
= weight of solvent in kg= 0.00144 kg

Therefore, the molality of solution will be, 13.38 mole/kg.

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