Question

The mole fraction of glucose in its aqueous solution having 755 mm of Hg vapour pressure at 373K is (VP of H₂O at 100°C 760 mm of Hg)
Answer in fraction​

Answer 1

Answer:

The expression for the relative lowering in the vapor pressure and the mole fraction of solute is

P

ΔP

=

N

n

For 1 L of solution

760

10

=

55.56

n

Thus, the number of moles of solute n=0.731

Thus, the mole fraction of solute =

55.56

0.731

=0.013

The molarity of the solution is

1

0.731

=0.731M