Question

The mole fraction of glucose in point 1 molal aqueous solution of glucose will be

Answer 1

Answer: The mole fraction of solvent in 0.1  molal aqueous solution is 0.9982.

Explanation:

1 molal aqueous solution means that 1 mol/kg that is 1 mol of solute is present in the 1000 g of the water(here the aqueous means that solvent is water).

Moles of solvent =

Moles of solute =  0.1 mol (given)

Moles of solvent =\frac{\text{mass of the water}}{\text{Molar mass of the water}}=\frac{1000 g}{18 g/mol}=55.55 mol

Moles of solute =  0.1 mol (given)

\chi_{solvent}=\frac{\text{moles od solvent}}{\text{Moles of solvent+Moles of Solute}}=\frac{55.55}{55.55+0.1}=0.9982

The mole fraction of solvent in 0.1  molal aqueous solution is 0.9982.