Question

The mole fraction of NaOH in 20% (w/w) aq NaOH solution is

Answer 1

Answer:

Explanation:

Mole fraction = nA /nA +nB

Given 20% (w/w) ie 20g NaOH  in 80 g water

Moles of NaOH = mass / mol mass  =20 /40 = 1/2

moles of water = 80/18 = 5

Total moles = 5.5

mole fraction of NaOH=  0.5 / 5.5 = 1/11

                                     = 0.09

Mole fraction of h20  = 1- 0.09  =0.91

Answer 2

Answer:

here is ur ans

Mole fraction = mole of naoh / moles of naoh(aq)

= 20/40 ÷ 20/40 + 100/40

= 1/6 ans...