The mole fraction of naoh in 5 molal aqueous naoh solution is
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Hey Dear,
◆ Answer -
Mole fraction of NaOH = 0.0826
● Explaination -
# Given -
m = 5 m
# Solution -
5 m NaOH solution contains 5 moles of NaOH in 1 kg of water.
W1 = 1000 g
n2 = 5 mol
Moles of water will be -
n1 = W1 / M1
n1 = 1000 / 18
n1 = 55.56 mol
Mole fraction of NaOH in aqueous solution -
X2 = n2 / (n1 + n2)
X2 = 5 / (55.56 + 5)
X2 = 0.0826
Therefore, mole fraction of NaOH is 0.0826 .
Thanks dear...
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