Question

the mole fraction of the solute in 4.5m aqueous solutuin is?
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Answer 1

Answer:

aquesous solution is 45/10

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Answer 2

The mole fraction of the solution is 0.075.

Given,

Molality of the aqueous solution=4.5 molal.

To find,

the mole fraction of the solute in aqueous solution.

Solution:

• Molality is defined as the moles of a substance(solute) in 1 Kg of solvent.
• Its unit is moles/Kg or molal.

• Mole fraction is equal to the ratio of the mole fraction of a solute to the total moles of the components(solute and solvent) of the solution.
• $Xa=\frac{na}{na+nb}$.
• It has no unit.

4.5 molal represents that 4.5 moles of solute are present in 1 Kg of solvent(water).

Mass of water(solvent)=1 Kg

Mass of water=1000 g.

The molar mass of water is 18 g.

Moles of water present will be:

$=\frac{1000}{18} \\=55.56 moles.$

The mole fraction of the solute will be:

$Xa=\frac{na}{na+nb}\\Xa=\frac{4.5}{55.56+4.5} \\Xa=\frac{4.5}{60.06}\\ Xa=0.075.$

Hence, the mole fraction is 0.075.

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