Question

the mole fraction of urea in 1 molal ethanolic solution of the Compound is




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Answer 1

Answer:

hope this will help you

Answer 2

The mole fraction of urea in the given solution is 0.044

Explanation:

We are given:

1 molal of urea in ethanol

This means that 1 mole of urea is present in 1 kg or 1000 g of ethanol

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of ethanol = 1000 g

Molar mass of ethanol = 46 g/mol

Putting values in above equation, we get:

$\text{Moles of ethanol}=\frac{1000g}{46g/mol}=21.74mol$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

Mole fraction of urea, $\chi_{urea}=\frac{n_{urea}}{n_{urea}+n_{ethanol}}=\frac{1}{1+21.74}=0.044$

Mole fraction of ethanol, $\chi_{ethanol}=\frac{n_{ethanol}}{n_{urea}+n_{ethanol}}=\frac{21.74}{1+21.74}=0.956$

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