The mole fraction of water in a mixture containing equal number of moles of water and ethanol is:
i) 1 ii) 0.5 iii) 2 iv) 0.25 (1)
b) The following are the vapour pressure curves of a pure solvent and a solution of a non-volatile solute in it.
Based on the above curves answer the following questions.
i) What do the curves A and B indicates? (1)
ii) Explain why the value of Tb is greater than that of Tb
0
.
Answers
Answered by
0
Answer:
According to Raoult's law, p=p
0
×x
Where,
p= partial vapour pressure of the solvent
p
0
= vapour pressure of the solvent
x= mole fraction of solvent.
The mole fraction of pure solvent =1−0.2=0.8
Substitute values in the above expression.
80=p
0
×0.8
Hence, p
0
=100 torr
Option C is correct.
Answered by Krisha
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Answer:
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