the mole fraction of water in a sulphuric acid solution is 085.calculate the molality of the solution
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mole fraction of solute +mole fraction of solvent =1
mole fraction of solute=1_ mole fraction of solvent
1_0.85=0.15
molefraction of solute =molality ×molecular weight of solvent÷1000
0.15=molality ×18÷1000
molality =8.3
mole fraction of solute=1_ mole fraction of solvent
1_0.85=0.15
molefraction of solute =molality ×molecular weight of solvent÷1000
0.15=molality ×18÷1000
molality =8.3
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