Question

The mole of oxygen atoms present in 2 moles of a compound, which consists of a bivalent metal and
a chlorate ion is
(1) 4 mole
(2) 6 mole
(3) 8 mole
(4) 12 mole

Answer 1

Answer: option (4): 12 moles

Explanation:

We are given that,

The bivalent metal “M²⁺” and Chlorate ions “ClO₃⁻¹” combines together to form M(ClO₃)₂ i.e.,  

M²⁺ + ClO₃⁻¹ → M(ClO₃)₂

In the compound so formed we can see that,

1 mole of compound “M(ClO₃)₂” consists of = 3 * 2 = 6 moles of oxygen atoms

∴ 2 moles of the compound “M(ClO₃)₂” will have = 6 * 2 = 12 moles of oxygen atoms

Thus, 12 moles of oxygen atoms are present in 2 moles of the compound M(ClO₃)₂.