the mole percentage of O2 in a mixture of 7 grams of N2 and 8 grams of O2 is
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Answer:
MOLE PERCENTAGE MEANS MOLE FRACTION ×100...
Explanation:
WE ARE GIVEN 7gms N2 means mole of N2 =
7÷28...
No. of moles of O2 = 8÷32...
Therefore Mole percentage of O2 = NO. OF MOLES OF O2/TOTAL MOLES IN MIXTURE
=1÷4/1÷4+1÷4
=1÷4/2÷4
=1/2
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