Question

The molecular formula of a compound in which double bond
is present between C & C :
(a) CₙH₂ₙ + 2 (b) CₙHₙ
(c) CₙH₂ₙ (d) CₙH₂ₙ₋₂

Answer 1

The molecular formula of a compund in which double bond is present between C & C is CₙH₂ₙ since

1) In CₙH₂ₙ + 2 

put n=1

then it will be CH4 which is an alkane

2) In CₙHₙ

put n=1

then it will be CH which not anything.

3) In CₙH₂ₙ

put n=1

then it will be CH2 which is not possible in alkene but at

n=2

it will be C2H4 which is an alkene

4) In CₙH₂ₙ₋₂

put n=2

then it will be C2H2 which is an alkhyne

5) so option (c) is correct.

Answer 2

The compound having double bond is   H2 - C = C - H2 which is an alkene.

Option (C) is correct.

Explanation:

In order to know the presence of double bond among the following compounds put the values of n= 1 and n= 2 respectively.

So

(a) n = 2 it will be CH4 which is an alkane i.e methane

(b) n = 2  it will be C2H2  an alkyne

(c) n = 2 it will be C2H4 which is an alkene having double formula.

             H2 - C = C - H2

Thus the compound having double bond is   H2 - C = C - H2 which is an alkene.

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