Question

the molecular formula of acetic acid and ethene is CH3COOH and C2H4, their empirical formula will be :
C2OH and CH2
CH2O and CH2
CO2H and CH
CH2O and CH2

Answer 1

Emperical formula:

• it is the simplest formula of any compounds.
• $\rm \dfrac{emperical \: formula}{molecular \: formula} = n$
• n = common factor in the compound.

★ Acetic acid

• $\rm CH_3COOH = C_2H_4O_2$
• $\rm (CH_2O)_2$
• n = 2

$\implies\bf emperical \: formula = CH_2O$

★Ethene

• $\rm C_2H_4 = (CH_2)_2$
• n = 2

$\implies\bf emperical \: formula = CH_2$

Answer 2

Explanation:

Emperical formula:

it is the simplest formula of any compounds.

$\rm \dfrac{emperical \: formula}{molecular \: formula} = n$

n = common factor in the compound.

★ Acetic acid

$\rm CH_3COOH = C_2H_4O_2$

$\rm (CH_2O)_2$

n = 2

$\implies\bf emperical \: formula = CH_2O$

★Ethene

$\rm C_2H_4 = (CH_2)_2$

n = 2

$\implies\bf emperical \: formula = CH_2$