Question

The molecular formula of the consecutive members of a homologous are C6H14 and C7H16. Write the molecular formulae of members having 9 and 11 carbon atoms of this homologous series.

Answer 1

Answer: For 9 carbon atoms: C9H20

              For 11 carbon atoms: C11H24

Explanation: Looking at the given formulas, i.e C6H14 and C7H16, we can see that the number of Hydrogen atoms is MORE than two times the number of Carbon atoms. This forms a Homologous series of Alkane.

  The homologous series of Alkane is led by the formula C(n)H(2n+2), where (n) is the number of Carbon atoms. Hence, we have, n=9. Therefore, C(9)H[2(9) +2] i.e C9H20.

  Similarly for n=11, C11H24

Answer 2

Answer:

For 9 carbon atoms : C9H20

For 11 carbon atoms : C11H24

Explanation:

C6H14 AND C7H16 ARE ALKANE HOMOLOGOUS SERIES .

SO, USE GENERAL FORMULA : CnH2n+1.

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