The molecular formula of the consecutive members of a homologous
Are C6H14 and C7H16 write the molecular formula of members having 9 and 11 carbon atoms of this homologous series
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Answer:
the 9 carbon atoms having =C9H20
the 11 carbon atoms having =C11H24
Explanation:
The homologous series of Alkane is led by the formula C(n)H(2n+2), where (n) is the number of Carbon atoms. Hence, we have, n=9. Threfore, C(9)H[2(9) +2] i.e C9H20.
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