Question

the molecular mass of sulphuric acid is 98.if49 gram of acid in dissolves in water to make 1 litre of solution what will be strength of acid

Answer 1

Answer:49g/L or 2mole/L

Explanation:

Clearly 49 gram of acid dissolves in 1L so strength is 49g/L and if writing in moles 49grams = 98/49 = 2mol/L

Answer 2

The strength of acid is 49 g/L

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of sulfuric acid = 49 g

Molar mass of sulfuric acid = 98 g/mol

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of sulfuric acid}=\frac{49}{98\times 1}\\\\\text{Molarity of sulfuric acid}=0.5M$

To calculate the strength of acid, we use the equation:

$\text{Strength of acid}=\text{Molarity}\times \text{Molar mass}$

Putting values in above equation, we get:

$\text{Strength of acid}=0.5mol/L\times 98g/mol=49g/L$

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