Question

The molecular mass of two gases is 25:45 repectively.Find the diffusion rate in ratios.​

Answer 1

Explanation:

An important thing to keep in mind here is that you're dealing with rates of diffusion, not with rates of effusion. Because the two gases are presumably kept under the same conditions for pressure and temperature, you can find a relationship between their rates of diffusion and their molar masses.

Now, according to Graham's Law of Diffusion, the rate of diffusion of a gas is inversely proportional to the square root of its density

∣∣ ∣ ∣∣¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯aarate∝1√densityaa∣∣ ∣∣−−−−−−−−−−−−−−−−−−−−

However, because the density of a gas is directly proportional to its molar mass, you can use the ideal gas law equation

∣∣ ∣∣¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯aaPV=nRTaa∣∣−−−−−−−−−−−−−−− , where

P - the pressure of the gas

V - the volume it occupies

n - the number of moles of gas

R - the universal gas constant, usually given as 0.0821atm⋅Lmol⋅K

T - the absolute temperature of the gas

to show that the rate of diffusion of a gas is also inversely proportional to the square root of molar mass.

Since you know that the number of moles can be expressed as the ratio between the mass of the sample, m, and the molar mass of the gas, MM

n=mMM

you can say that

PV=mMM⋅RT

Rearrange this to get

P⋅MM=ρmV⋅RT

ρ=PRT⋅MM