Question

the molecular velocities of two gases at the same temperature u1 and u2 and their molar masses are m1 and m2 respectively then its expression is

Answer 1

The molecular velocities of two gases at the same temperature are u1 and u2 and their molar masses are m1 and m2 respectively.

Then their kinetic energy will be:

$\frac{1}{2}m_{1}u_{1}^{2}=\frac{1}{2}m_{2}u_{2}^{2}$

that can be written as:

$m_{1}u_{1}^{2}=m_{2}u_{2}^{2}$

So the expression is as follows:

$m_{1}u_{1}^{2}=m_{2}u_{2}^{2}$

Answer 2

Answer: it will help u

Explanation:

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