Question

the molecular weight of a gaseous substance is 200 gram. what is the volume of 5g of the substance at N.T.P?​

Answer 1

Answer:

Gas constant is the value is 0.0821 L.atm.K

−1

.mol

−1

applying PV=nRT

n=mass of substance/molecular mass of substance

n=0.5g / molecular mass of gas

Putting values in equation

1×1.12=0.5 g / molecular mass of gas× 0.0821 L.atm.K

−1

.mol

−1

×273.15

Molecular mass=

1×1.12

0.5×0.0821×273.15

=10.5 g

Explanation:

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Answer 2

Given :

• Molar mass = 200 g
• Mass = 5 g

To find :

• Volume of 5g substance at NTP

Solution :

First , we need to find the moles of the gaseous substance .

As per the formula ,

$\implies\mathtt{ moles = mass / molar\: mass}$

⇒ moles = 5 / 200

⇒ moles = 1 / 40

⇒ moles = 0.025

As per the relation ,

$\implies \mathtt{moles = volume / 22.4 L (NTP )}$

⇒ volume = moles x 22.4

⇒ volume = 0.025x 22.4

⇒ volume = 0.56 L

The volume of the substance at NTP is 0.56 L .