The molecular weight of an organic compound is 90 it's empirical formula is CH2O then molecular formula is
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1
Answer:
C3H6O3
Explanation:
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Answer:
Empiricaz formula is CH 2O
Mass of Empirical formula =12+12+16=30g
Vapour density = Molar mass of compound/2
∴90= Molar mass/2
Molar mass of compound =180g
On dividing the
Empirical formula mass/Molecular formula mass
n= 180/30
=6
On multiply each atom of empirical formula by n we get actual molecular formula
C×+H 2 ×6+O×6=C 6H 12 O 6
The molecular formula of compound is
C 6 H 12O6
with molar mass 180.
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