Question

The molecular weight of haemoglobin is 67200. It contains 0.334% iron by weight. Find out the number of iron atoms present in 1 molecule of haemoglobin.

Answer 1

Percentage of Fe = 0.334% molecular weight of haemoglobinWeight of Fe present = (0.334/100) × 67200 = 224.4.........one Fe weighs 55.8 gTherefore, 224.4/55.8 = 4Hence, 4 atoms of iron are present in one molecule of haemoglobin.

Answer 2

Answer:4 =Fe atoms

Explanation:

0.334% =no of atoms x56/67200 *100

0.334x67200/5600= 4 Fe atoms