Question

The molecular weight of haemoglobin is about 65,000 g/mol. Haemoglobin contains 0.35% Fe by mass. How many iron atoms are there in a haemoglobin molecule?

Answer 1

Hi

Here is your answer

Weight of Fe present =35/100×65000

=227. 5

So one Fe weights 55.8 grams

Hence no. Of Fe atoms present = 227.5÷55.8=4(approx)


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Answer 2

The number of iron atoms in the haemoglobin molecule are 24.45625 x 10^23.

Given,

Mass percentage of Fe(iron) in haemoglobin=0.35%

Molecular weight of haemoglobin=65,000 g/mol.

To find,

the number of iron atoms in the haemoglobin molecule.

Solution:

• Mass percentage of a substance in a compound is defined as the mass of that substance in 100 g of the compound.

This means that 0.35 g of iron is present in 100 g of haemoglobin so the total weight of iron in the molecule will be:

=0.35/100 x 65000

=3.5 x 65

=227.5 g.

• Moles are equal to the ratio of the given mass upon the molar mass.
• Molar mass of iron is 56 g/mol.

Moles of Fe will be=227.5/56

=4.0625.

1 mole contains 6.02 x 10^23 particles.

Number of Fe atoms in haemoglobin will be=4.0625 x 6.02 x 10^23

=24.45625 x 10^23

Hence, 24.45625 x 10^23 atoms of iron are present.

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