The molecular weight of O2 and N2 are 32 and 28 respectively. At 15degree C , the pressure of 1 gm will be the same as that of 1 gm in the same bottle at the temperature
Answers
Answered by
1
Answer:
Temperature of O2 =273+15=298K
Temperature of N2 =x
As P∝nT, as pressure is same.
⟹n1T1=n2T2⟹(321)(298)=(281)(x)⟹x=3228×298=260.75K
Temperature in oC=260.75−273=−13oC
Explanation:
If the answer is correct pls mark me in Brain list
Answered by
1
Answer:
please mark it as brainlist
please follow me
read attachment carefully
Attachments:
Similar questions